Double · two matches: Merida, Daniel — Rublev, Andrey · Nakashima, Brandon — Michelsen, Alex

Which match might surprise us with the number of sets? I think the encounter between Merida and Rublev is quite capable of that. The expected score here could be close to 3:1 in favor of Rublev, and the likelihood of more than 3.5 sets being played seems justified. Daniel Merida is showing decent form: he has won three out of his last four matches, including a victory over Cilic with a score of 3-6, 6-1, 6-1. He has a good record on hard courts this year — 19 wins to 7 losses. Andrey Rublev, on the other hand, has a record of 13-9 on hard courts and recently came back from two sets down against Virtanen. This indicates that both players are capable of putting up a fight.

As for their head-to-head encounters, there have been none between these tennis players at the main level. However, considering the current form of both, we can expect a tense match. Rublev is an experienced player with a high level of motivation at a tournament like the US Open. He should be ready for a battle and won’t let Merida take the upper hand easily.

Now let's move on to the second match: Nakashima against Mikelson. Both tennis players are on a ten-match winning streak, making their meeting particularly interesting. Brandon Nakashima is ranked 17th in the ATP world rankings and has an excellent record on hard courts — 22 wins to 9 losses this season. Alex Mikelson also looks good with a similar hard court record and an overall record of 32-19 this year. This will be their first meeting at the ATP level, and both players will be eager to extend their successful streaks.

In conclusion, betting on over 3.5 total sets in the Merida vs Rublev match seems logical given the form and motivation of the players. A bet on Nakashima's victory also looks justified due to his consistent results and high level of play in recent matches.

Let's take over 3.5 total sets at odds of 1.51 and Nakashima to win at odds of 1.44; the total odds for the parlay will be 2.17.